2(2x^2+13x-57x=0)

Solution for 2(2x^2+13x-57x=0) equation:

2(2x^2+13x-57x=0)

We move all terms to the left:

2(2x^2+13x-57x-(0))=0

We multiply parentheses

4x^2+26x-114x+0=0

We add all the numbers together, and all the variables

4x^2-88x=0

a = 4; b = -88; c = 0;
Δ = b2-4ac
Δ = -882-4·4·0
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-88}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+88}{2*4}=\frac{176}{8}
=22
$